4/t^2*4*1/4=1/t-2

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Solution for 4/t^2*4*1/4=1/t-2 equation: 


D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(1*4*(4/(t^2)))/4 = 1/t-2 // - 1/t-2

(1*4*(4/(t^2)))/4-(1/t)+2 = 0

(4*(4/(t^2)))/4-t^-1+2 = 0

4*t^-2-t^-1+2 = 0

t_1 = t^-1

4*t_1^2-1*t_1^1+2 = 0

4*t_1^2-t_1+2 = 0

DELTA = (-1)^2-(2*4*4)

DELTA = -31

DELTA < 0

t belongs to the empty set

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